day la 1 bai toan thuoc ve chyen nhang cong trinh thuy loi bon em.Noi chung la em nho cac bro jup em cai vong lap While ay.ket qua thi dung roi nhung ma no ko chiu dung lai.
Nom na thi bai toan la the nay.Bai toan toi uu,Cac bac nhin thay cai ma tran K chua,Day,cu lap nhu the den thi nao cac phan tu o hang 1 cua K deu duong thi dung lai.
Nom na thi bai toan la the nay.Bai toan toi uu,Cac bac nhin thay cai ma tran K chua,Day,cu lap nhu the den thi nao cac phan tu o hang 1 cua K deu duong thi dung lai.
Code:
function thu
K=[1 -3 -5 0 0 0 0;0 1 0 1 0 0 4;0 0 1 0 1 0 6;0 3 2 0 0 1 18]
disp('tim cot quay va bien thay the')
m=3
n=2
while 1
K(1,:)>0
for i=2:n+1
min(K(1,:));
if K(1,i)==min(K(1,:))
disp('cot quay la')
cotquay=i
disp('bien thay the la')
bienthaythex=i-1
end
end
if K(:,cotquay)<0
disp('phuong an nghiem ban dau khong nam tren bien')
disp('chon lai buoc 0')
end
disp('tim hang quay va bien bi thay the')
K4=K(:,cotquay)
K5=K(:,m+n+2)
teta=K5./K4
kq=[];
for i=2:m+1
if (teta(i,1)>0)&(teta(i,1)~=inf)
kq = [kq, teta(i,:)];
end
end
teta1=kq
tetamin=min(teta1)
for i=2:m+1
if teta(i,1)==tetamin
disp('hang quay la')
hangquay=i
disp('bien bi thay the la')
bienbithaythex=i+1
end
end
K(hangquay,:)
K(hangquay,cotquay)
hesohangcobienmoi=K(hangquay,:)/K(hangquay,cotquay)
if hangquay==m+1
i=1:hangquay-1
K(i,:)=K(i,:)-K(i,cotquay)*hesohangcobienmoi
K(hangquay,:)=hesohangcobienmoi
else
for i=1:hangquay-1
K(i,:)=K(i,:)-K(i,cotquay)*hesohangcobienmoi
K(hangquay,:)=hesohangcobienmoi
end
for i=hangquay+1:m+1
K(i,:)=K(i,:)-K(i,cotquay)*hesohangcobienmoi
K(hangquay,:)=hesohangcobienmoi
end
end
K
if K(1,:)>0
break
end
end
end
ngohaibac
Comment